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Old 02-26-2010, 06:53 PM   #1
icygalz
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Registered: Feb 2010
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Get number between / /


Hi,

i have:

avg = 97.384/97.799/98.561/0.539 ms

And I want to get the result

avg= 97.799 ms

I am confused how to do it directly so I am planning to erase the first number and slash so it will look like this

avg = 97.799/98.561/0.539 ms

by

Code:
sed 's@=.*/@ @g'
but it is giving strange output

avg 0.296 ms


Can anyone help me?

Thanks
 
Old 02-26-2010, 07:01 PM   #2
smeezekitty
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Registered: Sep 2009
Location: Washington U.S.
Distribution: M$ Windows / Debian / Ubuntu / DSL / many others
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sed 's/\//\n/g' | head -n 2 | tail -n 1

Last edited by smeezekitty; 02-26-2010 at 07:17 PM. Reason: Fixed sed syntax
 
Old 02-26-2010, 08:02 PM   #3
Tinkster
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Distribution: slackware by choice, others too :} ... android.
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Quote:
Originally Posted by icygalz View Post
Hi,

i have:

avg = 97.384/97.799/98.561/0.539 ms

And I want to get the result

avg= 97.799 ms

I am confused how to do it directly so I am planning to erase the first number and slash so it will look like this

avg = 97.799/98.561/0.539 ms

by

Code:
sed 's@=.*/@ @g'
but it is giving strange output

avg 0.296 ms


Can anyone help me?

Thanks
Almost, slightly oversimplified. Not sure where the 0.296
might have come from, if I run your example it gives:
Code:
avg  0.539 ms
which is in line with your input.

Try
Code:
  echo "avg = 97.384/97.799/98.561/0.539 ms" |sed -r 's@ = [^/]+/([^/]+).*@= \1 ms@'
avg= 97.799 ms

Last edited by Tinkster; 02-26-2010 at 08:04 PM.
 
1 members found this post helpful.
Old 02-26-2010, 09:35 PM   #4
icygalz
LQ Newbie
 
Registered: Feb 2010
Posts: 3

Original Poster
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Thanks guys^_^
 
Old 02-26-2010, 09:39 PM   #5
schneidz
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Registered: May 2005
Location: boston, usa
Distribution: fc-15/ fc-20-live-usb/ aix
Posts: 5,167

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Code:
avg=`echo 97.384/97.799/98.561/0.539 ms | awk -F / '{print $2}'`
 
  


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