[SOLVED] Get number between / /

icygalz · 02-26-2010, 05:53 PM

Hi,

i have:

avg = 97.384/97.799/98.561/0.539 ms

And I want to get the result

avg= 97.799 ms

I am confused how to do it directly so I am planning to erase the first number and slash so it will look like this

avg = 97.799/98.561/0.539 ms

by

Code:

sed 's@=.*/@ @g'

but it is giving strange output

avg 0.296 ms

Can anyone help me?

Thanks

smeezekitty · 02-26-2010, 06:01 PM

sed 's/\//\n/g' | head -n 2 | tail -n 1

Tinkster · 02-26-2010, 07:02 PM

Quote:

Originally Posted by icygalz

Hi,

i have:

avg = 97.384/97.799/98.561/0.539 ms

And I want to get the result

avg= 97.799 ms

I am confused how to do it directly so I am planning to erase the first number and slash so it will look like this

avg = 97.799/98.561/0.539 ms

by

Code:

sed 's@=.*/@ @g'

but it is giving strange output

avg 0.296 ms

Can anyone help me?

Thanks

Almost, slightly oversimplified. Not sure where the 0.296
might have come from, if I run your example it gives:

Code:

avg  0.539 ms

which is in line with your input.

Try

Code:

  echo "avg = 97.384/97.799/98.561/0.539 ms" |sed -r 's@ = [^/]+/([^/]+).*@= \1 ms@'
avg= 97.799 ms

icygalz · 02-26-2010, 08:35 PM

Thanks guys^_^

schneidz · 02-26-2010, 08:39 PM

Code:

avg=`echo 97.384/97.799/98.561/0.539 ms | awk -F / '{print $2}'`