[SOLVED] concatenate couple of variable's holding path details

newuser85 · 09-01-2015, 10:02 AM

Hi All,

I am trying to concatenate two variables in shell script holding path details and then appending one more path to it.

#!/usr/bin/sh

pl="lsapps"
LAWDIR='E:\VHA_Script\Scripts\'
localdir=$LAWDIR\$p1\work\NTCONIN

echo $localdir

***************************************************

Output - E:\VHA_Script\Scripts\$p1workNTCONIN

but my expectation is to get E:\VHA_Script\Scripts\lsapps\work\NTCONIN (Path) stored in localdir

***************************************************

Fyi I am running the script on Cygwin. need your advice to resolve the issue. Thanks in advance.

schneidz · 09-01-2015, 10:18 AM

1. the path looks weird (ms-windows ?)

2. pl != p1

3. i think you would need to quote "$p1" so that the shell doesnt interpret the variable name as $p1work.

chrism01 · 09-01-2015, 09:29 PM

I agree with 1 & 2 above.
Also the '\' before '$pl' is unneeded and acts as an escape.
Try this

Code:

pl="lsapps"
LAWDIR='E:\VHA_Script\Scripts\'
localdir=${LAWDIR}${pl}\\work\\NTCONIN


echo $localdir

bash t.t
E:\VHA_Script\Scripts\lsapps\work\NTCONIN

Note the extra '\'s to make '\' a literal char instead of the escape-metachar

newuser85 · 09-02-2015, 04:16 AM

Hi,

Thanks for both of you.

1) Yes I am trying to execute the script on Windows using Cygwin.

2) Typo corrected.

3) tried localdir=${LAWDIR}${pl}\\work\\NTCONIN and now value is getting stored as expected.