bash script and sed
 

Hi,

I'm trying to write a bash script to find all lines containing two different strings in many files. I don't have access to egrep so I want to use sed for this purpose.
The files will look like this:
FileX
------
Info:18
Data:76
Contact:me@home.com
Start:1500

I want to generate a new file from these files with only the rows containing Data and Start. Something like this:

for y in `ls /file*.db`;
do sed '/Data|Start/p' $y > newfile
done

I'v tried to find a solution to this but not found it. Anyone have a suggestion for this?

Thanks,
Goran

Hi,

Use this as sed statement: Hope this helps.

Are you using the GNU version of sed? If so, you want "\|", rather than "|" as per the manual. Also, you probably want to use the -n option, to stop it printing out the entire pattern space.

Thank you druuna. It works. So simple.

You're welcome :)

Great you have a solution. Please mark as SOLVED :)

My solution also works.

The -r option tells sed to use extended regex, which supports operators such as "|", "+", and "()" without having to use backslashes.