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Old 03-13-2011, 02:59 PM   #1
Snoken99
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Thumbs up bash script and sed


Hi,

I'm trying to write a bash script to find all lines containing two different strings in many files. I don't have access to egrep so I want to use sed for this purpose.
The files will look like this:
FileX
------
Info:18
Data:76
Contact:me@home.com
Start:1500

I want to generate a new file from these files with only the rows containing Data and Start. Something like this:

for y in `ls /file*.db`;
do sed '/Data|Start/p' $y > newfile
done

I'v tried to find a solution to this but not found it. Anyone have a suggestion for this?

Thanks,
Goran
 
Old 03-13-2011, 03:02 PM   #2
druuna
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Hi,

Use this as sed statement:
Code:
sed -rn '/Data|Start/p' $y > newfile
Hope this helps.
 
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Old 03-13-2011, 03:04 PM   #3
Nylex
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Are you using the GNU version of sed? If so, you want "\|", rather than "|" as per the manual. Also, you probably want to use the -n option, to stop it printing out the entire pattern space.
 
Old 03-13-2011, 04:00 PM   #4
Snoken99
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Thank you druuna. It works. So simple.
 
Old 03-13-2011, 04:21 PM   #5
druuna
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You're welcome
 
Old 03-13-2011, 08:12 PM   #6
grail
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Great you have a solution. Please mark as SOLVED
 
Old 03-14-2011, 03:13 AM   #7
Nylex
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My solution also works.
 
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Old 03-14-2011, 11:05 AM   #8
MTK358
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Quote:
Originally Posted by Nylex View Post
Are you using the GNU version of sed? If so, you want "\|", rather than "|" as per the manual. Also, you probably want to use the -n option, to stop it printing out the entire pattern space.
The -r option tells sed to use extended regex, which supports operators such as "|", "+", and "()" without having to use backslashes.
 
  


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