Hi, All

I have solaris9 with SVM enabled.

metastat shows me swap device [d1] is 2GB But swap -s does not match 2GB and little large than swap device size.

# swap -l ==> swap -l shows that only d1 is swap device.
swapfile dev swaplo blocks free
/dev/md/dsk/d1 85,1 16 4202672 2377936

# swap -s ==> swap -s show SWAP is 1.4G+1.1G = 2.5GB
total: 1539808k bytes allocated + 128624k reserved = 1668432k used,
1203096k available

d1: Mirror ==> However, metastat shows d1 just has 2GB.
Submirror 0: d11
State: Okay
Submirror 1: d21
State: Okay
Pass: 1
Read option: roundrobin (default)
Write option: parallel (default)
Size: 4202688 blocks (2.0 GB) <<===

d11: Submirror of d1
State: Okay
Size: 4202688 blocks (2.0 GB)
Stripe 0:
Device Start Block Dbase State Reloc Hot Spare
c1t0d0s1 0 No Okay Yes


I wonder why swap -s has 0.5GB larger than d1 size.

Kindly pls help.

Gryan

A large part of RAM is part of virtual memory so is accounted as swap space when -s option is used.

From the swap manual page:

-s
...
These numbers include swap space from all configured
swap areas as listed by the -l option, as well swap
space in the form of physical memory.

Is it possible to just show swap capacity exluding the swap space of physical mem. I read through the manual of swap command. It seems that no
option to do that. But I want to confirm here. Also, I think I can use
[swap -s output] - swap device size to obtain the swap space of physical mem. I just wonder whether there is command for it.

Thank you.

Gryan

It is unclear what you are asking. Can you rephrase that and explain better what output you are expecting ?

Sorry for my poor description. I wonder whether there is command option to show swap device size and swap space of physical mem, respectively.