script not running in cronjob
 

set zar=0
set tot=0
for tot in 0
do
while read i
do
cd /opt/audible/logs/cdl/$i
d=`date|cut -d' ' -f1,2,3`
e=`date|cut -d' ' -f4|cut -d':' -f1`
f="$d $e:00"
zar=`cat aws_dynamic_partial.log |grep "${f}"|cut -d' ' -f14 | tr -s ',' ' '`
tot=`expr $tot + $zar`
echo $tot > /home/dingale/file
done
done < serverlist.txt
echo no of c programms running are $tot|mailx -s "No of c programmes running are $tot" dingale@domain.com



This script runs fine when fired manually
but gives blank value when run as cronjob.

Thanks,
Ingale D. N.

You're not specifying the all important magic header in scripts that tell your shell what interpreter will be running the script.

In this case, your script seems to be a sh/bash like script so you need to insert the following to very 1st line:

When run as a cronjob you need to ensure the paths are found in your script. The safest way to do this is to always specify the full path for each utility (eg /bin/grep instead of just grep)

Try this in your script and see if it helps?