what are the defaults for cpu (i386, i486...) when compiling
 

Hello Folks
I use checkinstall to create my own Slackware packages on Slackware 10.0. I always end up with some i386-packages since Checkinstall doesn't seem to recognize which flags were set (I haven't set any since I'm a newbee in this regard). Besides of this, I was wondering when compiling packages by using ./configure make make install, what environment variable is set by default (i386 or i486?, because all slack-packages are i486?)? And how could I change this if I would like to compile i686-packages as default?
Thanx in advance
Burna

If you don't set the flags or use a build script it will default to the architecture if your machine.

You mean, I have Pentium 4 and I get automatically i686 packages and do not need to change anything on the setup? I found these flags on the web.

CHOST="i686-pc-linux-gnu" CFLAGS="-march=i686 -O3 -pipe -fomit-frame-pointer" CXXFLAGS="-march=i686 -O3 -pipe -fomit-frame-pointer"

Would it make sense to use them and then where to put them on the right place?

Where is the architecture for the machine stored?

I know you can use 'arch' or 'uname -m' to find out. But where do these utilities get it from?

Thanks

uname is included. the compiler finds your machines arch.
This is the standard slackware CFLAGS line which will give you stuff compiled like slackware:
CFLAGS="-O2 -march=i486 -mcpu=i686"
See the thread:
http://www.linuxquestions.org/questi...hreadid=144372
I don't know what checkinstall will do with the names. I make my own pkgs using makepkg since the pkgs usually have to be exploded and tweaked anyway.

Thanks for the reply....