[SOLVED] How to read line by line a variable in bash? (Slackware Packages)

I'm saving a list of files to a bash variable and I want to read that variable line by line.

The code for saving the file list to a variable is:

 filelist_number="$((1 + "$(grep -n "FILE LIST:" /var/lib/pkgtools/packages/sc-7.16-x86_64-8 | cut -d : -f 1)"))"
filelist="$(sed -n "${filelist_number},\$p" /var/lib/pkgtools/packages/sc-7.16-x86_64-8)"
echo "${filelist}"

... and now I want to read "${filelist}" line by line. An example just doing "echo" of each line should be sufficient.

It's more of a general bash scripting question than slackware specific but just going off what you posted I think the following would work fine.

for ITEM in $(sed -n "${filelist_number},\$p" /var/lib/pkgtools/packages/sc-7.16-x86_64-8); do
  echo ${ITEM}
done

I assume filenames in filelist don't include whitespace. Then you can just read the contents of the variable into an array:

files=($filelist)
for f in ${files[@]}
do echo "$f"
done

Originally Posted by 0XBF It's more of a general bash scripting question than slackware specific but just going off what you posted I think the following would work fine. for ITEM in $(sed -n "${filelist_number},\$p" /var/lib/pkgtools/packages/sc-7.16-x86_64-8); do echo ${ITEM} done

Though I had something different in mind, that solution also worked to do what I wanted. Thanks.

Originally Posted by shruggy I assume filenames in filelist don't include whitespace. Then you can just read the contents of the variable into an array: files=($filelist) for f in ${files[@]} do echo "$f" done

That worked too. Thanks!

And I think there's an easier way to populate filelist. How about

filelist=$(sed '0,/^FILE LIST:/d' /var/lib/pkgtools/packages/sc-7.16-x86_64-8)

Originally Posted by shruggy And I think there's an easier way to populate filelist. How about filelist=$(sed '0,/^FILE LIST:/d' /var/lib/pkgtools/packages/sc-7.16-x86_64-8)

Awesome! Thank you, again!

Do you know if there is a way to do that without deleting the line matched?

This would only print from match to the end. Should do what you want I think.

sed -n '/^FILE LIST:/,$p' /var/lib/pkgtools/packages/sc-7.16-x86_64-8

Originally Posted by 0XBF This would only print from match to the end. Should do what you want I think. sed -n '/^FILE LIST:/,$p' /var/lib/pkgtools/packages/sc-7.16-x86_64-8

Yes, that is it. Thanks!