[SOLVED] Match text using awk and print before and after until line break

I am trying to print a blocking validation from simulation.txt. The matching string is "This is blocking validation." and i want to print two line before matching and print all line until blank break after match. What I am missing here?

===========================================
Miscellaneous Options.

This is a blocking validation.
===========================================
1 APPLE
2 BANANA
3 CAT
4 LEMON
5 LIME
6 LONDON
7 ORANGE
8 OAK
9 PENCIL
10 RED

This is not a blocking validation.
===========================================
Disable smilies in text

===========================================

Why is my mouse pointer wrong?

This is a blocking validation.
===========================================
1 spoil
2 dust

I am using this command but still need to print two line before match.

cat simulation.txt | awk '/This is a blocking validation./,/^$/'

     This is a blocking validation.
      ===========================================
       1    APPLE
       2    BANANA
       3    CAT
       4    LEMON
       5    LIME
       6    LONDON
       7    ORANGE
       8    OAK
       9    PENCIL
      10    RED

      This is a blocking validation.
      ===========================================
      1         spoil
      2         dust

Output | what i want is

Miscellaneous Options. This is a blocking validation. =========================================== 1 APPLE 2 BANANA 3 CAT 4 LEMON 5 LIME 6 LONDON 7 ORANGE 8 OAK 9 PENCIL 10 RED Why is my mouse pointer wrong? This is a blocking validation. =========================================== 1 spoil 2 dust

I cannot see any difference between your problem statement and your output. Please review and correct if necessary.

Daniel B. Martin

.

Search for “awk print two lines before match” (without quotes). I think the answer was there, but don’t know awk well enough to be sure...
Please share the answer when you find it.

Originally Posted by aungkhaingoo i want to print two line before matching and print all line until blank break after match. What I am missing here?

You'll have to save records till you find the initial match. Best would be to only keep two, and rotate through, discarding the oldest until the match. Ugly/lazy would be to keep everything. Your choice.

Originally Posted by danielbmartin I cannot see any difference between your problem statement and your output. Please review and correct if necessary. Daniel B. Martin .

My result is ==>

This is a blocking validation.
===========================================
1 APPLE
2 BANANA
etc

This is a blocking validation.
===========================================
1 spoil
etc

I also want to print also with Bold and underline text below ==>

Miscellaneous Options.

This is a blocking validation.
===========================================
1 APPLE
2 BANANA
3 CAT

Why is my mouse pointer wrong?

This is a blocking validation.
===========================================
1 spoil
2 dust

Originally Posted by syg00 You'll have to save records till you find the initial match. Best would be to only keep two, and rotate through, discarding the oldest until the match. Ugly/lazy would be to keep everything. Your choice.

Can you show me what is still missing to save records. I am a very new user in linux environment.

Look back at post #3

Originally Posted by grail Look back at post #3

Yes...and now that I'm back on my desktop, you can just click here

Here is what you initially requested.
A ring buffer holds the last lines.
When the /match/ is true; print the buffer, and keep printing until the NumberFields is 0.

awk '
  BEGIN { blen=2 }
  (n>=blen && /This is a blocking validation/) {
    for (i=bn; (i=(i+1)%blen)!=bn; ) print buf[i]
    print buf[i]
    pr=1
  }
  (pr)
  (NF==0) { pr=0 }
  { buf[bn=++n%blen]=$0 }
' file

Please add the decorations yourself!

Originally Posted by MadeInGermany Here is what you initially requested. A ring buffer holds the last lines. When the /match/ is true; print the buffer, and keep printing until the NumberFields is 0. awk ' BEGIN { blen=2 } (n>=blen && /This is a blocking validation/) { for (i=bn; (i=(i+1)%blen)!=bn; ) print buf[i] print buf[i] pr=1 } (pr) (NF==0) { pr=0 } { buf[bn=++n%blen]=$0 } ' file Please add the decorations yourself!

WOW you save me sir. This is what I really wanted result. Thank you.