LinuxQuestions.org - Using multiple values for single variable in a loop

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Using multiple values for single variable in a loop

Hello Guys,

I have a small loop problem as below.

I have 3 different values to be used while running the same script -

va1="some-value1"
va2="some-value2"
va3="some-value3"

Now I want to use these three variable values to be used for running the same command, like -

while (i=0,i<=3,i++)
do
bin/java -s (run something with $var);
done

Now I want $var taking the value of var1, var2 and var3 each time it runs,

so can someone please tell me how do we achieve the above?

I tried doing -

for $1 $2 $3

do
case 1
case 2
case 3
done

OR

while read a b c
do
<code assumed to have loop iteration>
done <<< $(command)

But it isnt working as expected... Would really appreciate your help on this.

Thanks,
Brian

Very simply, don't use separate variables. Whenever you have lists of related entries, you should use an array.

http://mywiki.wooledge.org/BashGuide/Arrays
http://mywiki.wooledge.org/BashFAQ/005

Code:



va[0]="some-value1"

va[1]="some-value2"

va[2]="some-value3"



for (i=0;i<=2;i++); do

        bin/java -s "${va[i]}"

done

[P.S. The syntax for your loop was all wrong. A while loop does not use a c-style counter. The correct form to use is shown above. http://mywiki.wooledge.org/BashGuide...ndConditionals ]

(This is of course assuming you're using bash or another advanced shell. Posix doesn't define arrays, so #!/bin/sh -style scripts shouldn't have them. )

Also, please use [code][/code] tags around your code and data, to preserve formatting and to improve readability.