howto pass argument with a script to execute a command

z_haseeb · 05-10-2017, 07:47 AM

I have a bash script, name script.sh with below data. I want to ran script.sh start which only triggers(ip route add 10.10.20.1 via 192.168.24.1 dev eth0 src 192.168.24.100) and if I run script.sh stop which only triggers (ip route del 10.10.20.1 via 192.168.24.1 dev eth0 src 192.168.24.100). When I run the below script, it executes but the ip route command cant run. please advice, I am not much good in code.

#!/bin/bash
start ()
{
ip route add 10.10.20.1 via 192.168.24.1 dev eth0 src 192.168.24.100
}
stop ()
{
ip route del 10.10.20.1 via 192.168.24.1 dev eth0 src 192.168.24.100
}

pan64 · 05-10-2017, 07:59 AM

do you know how to use case in bash?
http://tldp.org/LDP/Bash-Beginners-G...ect_07_03.html

michaelk · 05-10-2017, 08:20 AM

Code:

start () {
 ...
}
stop () {
 ...
}

Basically your script contains two functions. Functions are a group of commands that are not run until "called" by the script and your script as posted never calls start or stop. As suggested you can test your command line argument via a case statement to call your functions.

BW-userx · 05-10-2017, 08:38 AM

Functions BASH

Chapter 24. Functions
8. Functions
24.1. Complex Functions and Function Complexities
Case Statements BASH
7.3. Using case statements

Shebang (Unix)
Shebang (Linux)

z_haseeb · 05-11-2017, 07:04 AM

Thanks guys. I am able to do it.(I know there might be many mistakes in below script but it worked for me)

#!/bin/bash
DESTINATIONIP=10.10.20.1
GATEWAY=192.168.24.1
SOURCEIP=192.168.24.100
DEVICE=eth0
START="ip route add $DESTINATIONIP via $GATEWAY dev $DEVICE src $SOURCEIP"
STOP="ip route del $DESTINATIONIP via $GATEWAY dev $DEVICE src $SOURCEIP"

#####################################
# DONT CHANGE BELOW #
####################################

case "$1" in
start)
$START
;;
stop)
$STOP
;;
#esac