Quote:
Originally Posted by Fixit7
Outfile #0 does not contain any stream
Conversion failed!
I ended up with 2 zero byte files. :-(
What's up with that ?
It should have at least saved my original.
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Did you type it without the -i?
e.g.:
Code:
ffmpeg file.mp4 file.mp3
Because that will cause it to overwrite, it will also give you a warning first.
Code:
File 'file.mp4' already exists. Overwrite ? [y/N]
The
-i defines the input stream. Since I am guessing you did not define file.mp4 as the input stream, it assumed stdin was the input stream. Since stdin contained nothing and you defined two files to write to (file.mp4 and file.mp3) it wrote to those two files, prompting the user if a file already existed. That's my best guess on it's behavior.
