Here's what I'm trying to do: I'm attempting to create a Worker program which is to be called in a Coordinator program. The worker program needs to add two numbers from the argv and return the sum of those numbers. Basically my problem is some sort of syntax and I'm fairly new to this scripting stuff. Here's what I have:

#!/bin/bash
# Worker class for the program Coordinator

int worker(int argc, char *argv[]
{
int sum = 0;
sum = atoi(argv[1]) + atoi(argv[2]);
printf("I am child with PID %d", getpid());
printf("sum=%d\n", sum);
fprintf(atoi (argv[3]), sum, 4);
exit(sum);
}

Here's the errors:

~$./worker 2 4
./worker: line 4: syntax error near unexpected token `('
./worker: line 4: `int worker(int argc, char *argv[]'

why c in bash script?
should be enough

I'm trying to learn how forking works. What I'm gonna do is write the Coordinator program, which will fork new worker processes which will return their sums to new fork processes which will sum their sums..etc

say input is 5 3 2 3

worker1 would sum 5+3, return 8
worker2 would sum 2+3, return 5
worker3 would sum 8+5, return 13

thus the coordinator has to do no additions..

Updated code, still same error:

#!/bin/bash -x
# Worker class for the program Coordinator
#include<stdio.h>
#include <sys/types.h>

int main()
{
int work(int argc, char *argv [])

{
int sum = 0;
sum = atoi(argv [1]) + atoi(argv [2]);
printf("I am child with PID %d", getpid());
printf("sum=%d\n", sum);
fprintf(atoi(argv [3]), sum, 4);
exit(sum);
}
}

error:
~$ ./worker 2 4
./worker: line 6: syntax error near unexpected token `('
./worker: line 6: `int main() '

it's steel c inside of bash. bash and c are completely different things. If use c then create worker.c file and compile one.

Your right. I feel like a huge tard.