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Old 10-09-2011, 01:33 PM   #1
mystupidquestion
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Registered: Oct 2011
Posts: 6

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Why is my awk script producing extra spacing between the first and second column?


I wrote the following awk program:
Code:
cat "$fileToProcess" | awk '!(/LINUX|.inux/ || /\%/ || /.verage/ || /^$/)\
  {
    ("date --date="$1 $2" +%T") | getline correctTime;
      printf "%s\t", correctTime;
      for (i=3; i<NF; i++) printf "%s\t", $i;
      printf "\n"
      close("date --date="$1 $2" +%T")
    }'
to parse a file. The program works as expected, but I'm curious as to why the spacing between column 1 and column 2 is greater than the other columns. Here is a sample of the output:
Code:
20:10:01        all     19.31   0.00    2.90    0.24    0.00    
20:20:01        all     10.30   0.00    1.97    0.22    0.00    
20:30:01        all     11.36   0.00    2.26    0.19    0.00    
20:40:01        all     12.04   0.00    2.37    0.20    0.00
 
Old 10-09-2011, 01:42 PM   #2
colucix
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Registered: Sep 2003
Location: Bologna
Distribution: CentOS 6.5 OpenSuSE 12.3
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It's not an awk problem: it is the way the TAB separator works. By default TAB is 8-spaces length, the first string is 8-characters so that a complete TAB is printed out immediately after that. Look at the spacing of your output:
Code:
-------8-------8-------8-------8-------8-------8-------8-------8
20:10:01        all     19.31   0.00    2.90    0.24    0.00    
20:20:01        all     10.30   0.00    1.97    0.22    0.00    
20:30:01        all     11.36   0.00    2.26    0.19    0.00    
20:40:01        all     12.04   0.00    2.37    0.20    0.00
-------8-------8-------8-------8-------8-------8-------8-------8
Every field is followed by a variable number of spaces to fill the 8-characters TAB separator (included the last one).
 
1 members found this post helpful.
Old 10-09-2011, 01:51 PM   #3
mystupidquestion
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Registered: Oct 2011
Posts: 6

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ic. Thanks!
 
  


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