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#!/usr/bin/perl
=cut
Program to sum the squares of first 10 odd nos.
=cut
$count=0;
$i=0;
$sum=0;
while(1){
$i++;
if($i/2!=0){
print "$i\n";
$sum+=$i**2;
$count++;
}
if($i/2==0){
print "Ok\n";
}
if($count==10){
last;
}
}
print "The sum of first 10 odd nos. = $sum";
The o/p I get from this code is -
Code:
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The sum of first 10 odd nos. = 385
I am not able to figure it out. Why is the if statement
not working.
I know many disagree with me, but I do think it is lazy programming to write an infinite loop to be broken out of when you could simply
test your count variable in the while clause, or better yet, use a for loop as you know then end point.
I know many disagree with me, but I do think it is lazy programming to write an infinite loop to be broken out of when you could simply
test your count variable in the while clause, or better yet, use a for loop as you know then end point.
I know many disagree with me, but I do think it is lazy programming to write an infinite loop to be broken out of when you could simply
test your count variable in the while clause, or better yet, use a for loop as you know then end point.
That was my first try to the program. But thanks for the suggestion.
I know many disagree with me, but I do think it is lazy programming to write an infinite loop to be broken out of when you could simply
test your count variable in the while clause, or better yet, use a for loop as you know then end point.
That was my first try to the program. But thanks for the suggestion.
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