Hi All,

The scenario is

I have a log file with some data related to Some IDs.
I want to grep data with those IDs and have to put it in another log file.
Also i am fetching the IDs from another log file.
Therefore i have created a loop to fetch IDs 1 by 1
and grep it, if it founds something it will write it in another log file.
But the script i have created is not working good


It is overwriting the data on the first line itself and and giving the data according to the last ID.

For your reference i am pasting my script.

#!/bin/bash

var=`cat mac1.logs`

for i in $var;
do
#grep -a -i -F "$i" EXCEPTIONS_n1_thru_n4.logs >> test_exceptions.logs
echo $i

done

Kindly help me with this.

Thanks,
Aayush

Without having a clue as to the files contents, I assume $var has several lines and that's why you are using -F with grep. Thing is, you already break the variable when you iterate with "for i in var".

Have you tried using grep -F directly over $var?

Also, if you are processing strings in binary files, have a look at the "strings" command, which searches and extracts strings in binaries.

Thanks for the reply Juako.

Var has many lines it contains only the IDs, each ID is in new line.
For example the content in mac1.logs is like
0000B699569C
0000B6996155

I tried -F with $var, it is working perfectly fine.

I think i was just making the stuff complex by applying loops.

Thanks for the help.

Aayush.

I think you could also take out the var as well and just use the original file.

yep, this is a total one-liner:

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