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Hello!
I'm making a script, that counts the file types listed in the arguments in a folder, like this: ./dirstat png,txt,sh -d /Home
But there is a problem with it, I think in the line witch contains awk, because I'm trying to use a bash variable. I've signed the line, with big bold font. Pls help me! Thank you!!
this is the code (sorry, but the comment are hungarian) :
#!/bin/bash
-v var=val
--assign var=val
Assign the value val to the variable var, before execution of the program begins. Such variable values are available to the
BEGIN block of an AWK program.
so "-v p=$PATH" would set the "p" variable in the awk script to the bash $PATH variable.
Thank you, but I don't understand you reply, because I'm neither good in English, nor in BAsh, so if you or somebody else has time to give me an exact solution, I would apreciate it. Thank you!
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