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tostay2003

12-21-2007 08:15 AM

test number within a range

I am trying to test whether a number is assigned to a variable and is it within certain range (in a single line statement).

But the below code is giving an error saying -z is an unknow operator. Any clues on how to implement or mistake i have made

Code:

[[-z "$Id"] -o [!grep -q $Id [1-8]]] && _Function1

gnashley

12-21-2007 08:30 AM

When using complex tests (-o or -a) you can't use the double brackets. Try somethiong like this:

Code:

[[ -z "$Id" ]] || [[ ! $(grep -q $Id [1-8]) ]] && _Function1

or:

Code:

[ -z "$Id" -o ! $(grep -q $Id [1-8]) ] && _Function1

When you do use double brackets you have to leave a space between the brackets and the enclosed code.

ghostdog74

12-21-2007 08:42 AM

Quote:

Originally Posted by tostay2003 (Post 2998054)

Code:

[[-z "$Id"] -o [!grep -q $Id [1-8]]] && _Function1

KISS and take it step by step

Code:

id=8

case $id in 

    [1-8]) function1 ;; 

    *) echo "no";; 

esac

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