Shell

leszer · 07-07-2012, 08:43 PM

Hi. I'm having a heck of a time getting this to work..

I have a feeling the variable needs to be converted somehow to integer but not sure how to make this work and bc isn't an option.

Code:


#!/bin/bash


value1= cat File1
value2= cat File2
dividend= $((value2/value1))

echo $dividend

echo $value1
echo $value2

Any help appreciated. Thanks!

towheedm · 07-07-2012, 09:31 PM

BASH makes no distinction between data types for variables. That distinction is made only at the time that the variable is operated upon, I think.

To assign the output of a command to a variable you must use command substitution $( ... ).

Code:

value1="$(cat File1)"

Also:

Code:

dividend= $((value2/value1))    # should be
dividend= $(( value2/value1 ))

Of course your code as is will only work for only a single value in both File1 and File2.

leszer · 07-07-2012, 09:44 PM

Okay, I can see that the division is working now but it also gives me a 'command not found' when delivering the dividend.

Division.s: line 6: 4: command not found

leszer · 07-07-2012, 09:52 PM

Quote:

Originally Posted by leszer

Okay, I can see that the division is working now but it also gives me a 'command not found' when delivering the dividend.

Division.s: line 6: 4: command not found

^^ Pay no attention to this. lol Stupid space after the equal sign. Thanks, solved!

grail · 07-08-2012, 04:21 AM

Just add one more item, you can actually perform the assignment within the round brackets:

Code:

(( dividend = value2 / value1 ))

And yes the spaces are fine now