Shell scripting yes/no case?
 

Ok, so I am shell scripting retarded and I'm sure then is an easy question to answer.
I have to write a shell script that you must enter two command line arguments. If you enter in two arguments, then it asks if you have a typo, answering Yy or Nn. If no, it goes on to ask if it is a directory etc.

Do I use the case argument for the Yy or Nn? How do I get the shell to continue with the next test if I do use case?
Here is my shell script so far....

if test $# -ne 2
then
echo You must enter exactly 2 command line arguments, please try again.
exit 1
fi


if test $# -eq 2
then echo The command line arguments that you entered are $1 and $2. Did you
make a typo when entering the commands? Y or N.
read choice
case "$choice" in
Y|y) echo Program exiting because you said you had a typo. Please try again.;;
N|n)

if test ! -f $1 && $2
then echo Both files not located, please try again.
etc etc

is this correct or do I use another test like test "$choice" = Y|y??
I'm confused.. my linux prof doesn't like to explain anything..

I would use

read choice
case "$choice" in
Y|y) echo Program exiting because you said you had a typo. Please try again.
exit 1
;;
N|n)
;;
*) echo You must enter Y or N
;;
esac