shell script problem on sed.

chooi · 03-28-2005, 09:48 AM

Hi all,
here is my shell script.

Code:

backup_files()
{
  FSource=$1
  if [ $ABSOLUTE = "1" ]; then
        FTarget="$BACKUPPATH/`date '+%Y%m%d'`"
	
	desDir = "`echo $FILEPATH | sed -e 's/\/.*/ /'`"
	TmpTarget = $FTarget/$desFir
	if [ ! -d $TmpTarget ]; then
             mkdir -p $TmpTarget
        fi
	cp $DATAPATH/$FSource $Tmptarget/.

        
  else
        FTarget="$BACKUPPATH/`date '+%Y%m%d'`"
	TmpTarget = $FTarget/$FILEPATH
        
	TmpTrgt = "`cd $TmpTarget | cd .. | pwd`"
        if [ ! -d $TmpTrgt ]; then 
	     mkdir -p $TmpTrgt
        fi
	cp $FSource $TmpTrgt/.

  fi
}

what i want to do is :
let say the $FILEPATH = "/tmp/200/readme"
i want the desDir to capture only the "readme" by detect the last "/"
i write the statement like this:
desDir = "`echo $FILEPATH | sed -e 's/\/.*/ /'`"
But failed to get the value, it return empty.

Can anyone teach me how to use the sed or awk? thanks.

futhark · 03-28-2005, 10:09 AM

Well my suggestion would be not to use sed how awk. Since you seem to be using sh, here's something to try:

file=/tmp/readme.test
echo ${file##*/}

Dissecting ${file##*/} :

${file} : the var we work on

##*/ : replace from beginning of string, up to last occurence of /

The greatest bash doc around is this one:
http://www.tldp.org/LDP/abs/html/

sirclif · 02-10-2006, 03:08 PM

this is exactly what the command basename does

basename $FILEPATH

this will return 'readme'

kshkid · 02-10-2006, 11:35 PM

with just sed,

echo "/tmp/200/readme" | sed 's/^.*\///'