shell script find a line and the next line (grep?)

metalx1000 · 07-24-2007, 06:53 PM

Lets say I have the following text file

Code:

name
john123

phone:
123-213-4566

name
chris035

phone:
236-555-6546

name
bob56

phone:
333-666-9852

is there a way to find all the line that have "phone" and print them and the next line to make the out put look like this:

Code:

phone:
123-213-4566
phone:
236-555-6546
phone:
333-666-9852

I've looked into using grep awk & sed

I'm sure there is a way but I have yet to find it.

chrism01 · 07-24-2007, 07:00 PM

grep -A1 phone $file

This only works with GNU grep. Normal grep doesn't have -A (after) option ( see also -B => before)

dxqcanada · 07-24-2007, 07:02 PM

Awk

Awk can handle multiline records by specifying the field separator to be a newline and set the record separator to an empty string.

homey · 07-24-2007, 07:13 PM

Here's an example using sed.

Code:

sed -n '/phone/,+1 p' file.txt

metalx1000 · 07-24-2007, 08:25 PM

All great answers.

Thanks!!!

ghostdog74 · 07-24-2007, 08:41 PM

Code:

awk '/phone/{where=NR;print}NR==where+1 && where!=0 {print}' file