Hi there,

I'm really getting crazy to get the following done (linux):

The variables are clean and available in my script. No prob.

$old is an IP-address of a server, $new as well. replacement-file is an xml-file (the ip-address to be changed is within an xml-tag).

It should be trivial, but it isn't. I spent the last 3 hours reading about the problem, trying several different 'solutions' or workarounds.
It should work, the '"' should take care that the variables get expanded, but whatever I try the old server IP isn't replaced.

Plz, I need help. Any idea, anybody?
Regards,
jomann.

Hmm, that looks like it should work. Try it with the following and see if it helps:
It also depends on what the variables contain.....

Hi, thx a lot.

I already tried this one, too. but the double quotes eclosing the variables don't help. This doesn't work either.

Maybe some more info helps:

I get my variable from another file like this:
It's a .conf with a line like this:
srvadr 192.168.0.1

The .xml-file ($origfile, which gets the replacement) looks like this:
<DefaultDirectory value="smb://192.168.137.1/sharename" />

If I change the sed-cmd to:
or
it works perfect.

Regards, jomann.

Hi

Not sure, but try to run your script with:

bash -x scriptname

Then you see what's being sent to sed.

I think this is something simple.... Try the following:

I always thought so, too: it must be something simple (but after 3 hours staring at the code I got malfunction in my eyes & brain).

And indead it is... It works with the double quotes as it should:
The bash debug-mode revealed that I mixed up two IP addresses (I have some more variables), therefore my script was searching to replace something that wasn't there.

Thanks very much for your help!
jomann.

LOL Nice! Well glad you got it resolved. Mark your thread as SOLVED and give rep if you want to, thanks!

Josh

NB: There is the switch -i for in place substitution, so you could save the mv.