LinuxQuestions.org - s there a way to determine the owner of a file by using a script?

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s there a way to determine the owner of a file by using a script?

Example:

-rw-rw---- 1 xxx01 CGroup 20992 Nov 3 15:42 File001.doc
-rw-rw-r-- 1 xxx02 CGroup 19456 Aug 19 2002 File002.doc
-rw-rw---- 1 xxx03 CGroup 18432 Jul 13 2005 File003.xls
12345678901234567

I will know the file name, such as File002.doc. What I need to get is the owner xxx02. I could use cut to (ls -l testp | cut -b 17-21) in this example, but that would assume a 5 character owner name. Maybe there is another command that will get the file's owner? Any other ideas on determining the owner of a file by using a script?

Quote:

Originally Posted by DHoody

I will know the file name, such as File002.doc. What I need to get is the owner xxx02. I could use cut to (ls -l testp | cut -b 17-21) in this example, but that would assume a 5 character owner name.

This could be solved by cutting by field number (option: -f4). For this, you need to specify spaces as seperator (option: -d' '). Example:

Code:

ls -l File002.doc | cut -d' ' -f4

But because "cut" sees each space as a seperator, it may not be very reliable. A solution using "sed", "awk", "python", "perl" would better, but slower.

Another way by setting shell arguments:

Code:

set -- $(ls -l File002.doc)

# Now $1, $2, $3,.. are set to the different fields in

# the output of "ls":

echo "Owner: $3"

echo "Group: $4"

echo "Size:  $5"

But probably the most reliable, shortest and fastest way is to use "stat" instead of "ls":

Code:

stat -c%U File002.doc

Try using

Code:

ls -l filename | awk '{ print $3 }'

Wow...Not just one but, 3 great ways to get the job done. Thanks Hko and pljvaldez. stat will work best for my current script, but I see uses for the other options too. Excellent.

make that four ;)

Code:

billym.>set `ls -l ~/.profile`

billym.>echo $3,$4

billym,prima