[SOLVED] Replace a variable text with *

pedropt · 12-28-2017, 12:55 PM

more simple as it is , is impossible .

This one can be tested over the terminal without a script .

Quote:

echo 1234 | sed "s/1234/*/g"

The problem i have is that i can change the text only to 1 * , and i want sed to replace the number of character in the search with the same number of * .

The most easy answer from anyone to this would be :

CODE]
echo 1234 | sed "s/1234/****/g"
[/CODE]

But the example i am writing here is not what i will use in the code , because in my code that "1234" i a variable that does not have a fixed size of characters .

for a script for test it could be used this one with user input :

Code:

#!/bin/bash
echo -n "Write anything to be turned to * : "
read var
out=$(echo $var | sed "s/$var/*/g")
echo ""
echo "Your input $var was converted to $out"

Does anyone knows this one ?

Turbocapitalist · 12-28-2017, 01:07 PM

Think about replacing the numbers from a set [ ] like in the other question.

GazL · 12-28-2017, 01:12 PM

How about:

Code:

tr '[:print:]' '*'

Sefyir · 12-28-2017, 01:14 PM

Code:

echo 1234 | sed 's/./*/g'

danielbmartin · 12-28-2017, 01:17 PM

Quote:

Originally Posted by pedropt

Does anyone knows this one ?

Once again you posted a question, gave a sample input (only one) and no sample output. If you expect LQ people to help you, you must put in the effort to compose a good question.

Daniel B. Martin

.

pedropt · 12-28-2017, 01:18 PM

You guys are fast , thanks a lot for the tip .

Final code :

Code:

#!/bin/bash
echo -n "Write anything to be turned to * : "
read var
out=$(echo $var | sed "s/./*/g")
echo ""
echo "Your input $var was converted to $out"

NevemTeve · 12-28-2017, 01:32 PM

Hopefully $var won't be something like this: beware; rm -rf /

Edit: possible fix:

Code:

out=$(printf -- '%s' "$var" | sed "s/./*/g")

pedropt · 12-28-2017, 02:17 PM

Quote:

Hopefully $var won't be something like this: beware; rm -rf /

eheheheh , remove everything from the root by force , lol .

I am developing a quick script to work with velleman k8055 input/output card
https://www.velleman.eu/products/view/?id=351346

this sed code i asked is specifically to not show the password on the machine running the script .

https://s14.postimg.org/stwq2bbfl/keypad.jpg

This keypad script will work with k8055 input ports , and depending on the code inputed by user on a specific keypad connected to that card input ports can open a door or whatever user reminds him to do with it .

This will for github when finished .

MadeInGermany · 12-30-2017, 09:23 AM

With a bash builtin

Code:

out=${var//?/*}