[SOLVED] Remove the Last character from Variable

NetRock · 06-22-2010, 07:07 AM

Hi,

i have the following:

Quote:

echo %host%|sed "$s/.$//"

this would remove the Last character of the value assigned to the %host%. for example if my value is: abcd i get abc. but i am not able to assign the output. for example when i do

Quote:

set k=`echo %host%|sed "$s/.$//"`

after doing echo %k i get no output at the command prompt...!!
whereas when i just type:

Quote:

echo abcd|sed "$s/.$//"

at the command prompt i get abc

any ideas?? maybe some other ways to Remove the Last character...??

Thank you in advance for your help.

colucix · 06-22-2010, 07:26 AM

Hi NetRock, forgive my ignorance, but what kind of syntax is this? Which shell are you running on?

Code:

set k=`echo %host%|sed "$s/.$//"`

%host% and %k resemble DOS variables..

centosboy · 06-22-2010, 07:28 AM

Quote:

Originally Posted by NetRock

Hi,

i have the following:

this would remove the Last character of the value assigned to the %host%. for example if my value is: abcd i get abc. but i am not able to assign the output. for example when i do

after doing echo %k i get no output at the command prompt...!!
whereas when i just type:

at the command prompt i get abc

any ideas?? maybe some other ways to Remove the Last character...??

Thank you in advance for your help.

Code:

param=`echo host| sed 's/.$//g'`
echo $param

centosboy · 06-22-2010, 07:28 AM

Quote:

Originally Posted by colucix

Hi NetRock, forgive my ignorance, but what kind of syntax is this? Which shell are you running on?

Code:

set k=`echo %host%|sed "$s/.$//"`

%host% and %k resemble DOS variables..

that is what i initially thought...ksh??

centosboy · 06-22-2010, 07:30 AM

nope...

NetRock · 06-22-2010, 07:32 AM

Hi...

Thanks for your reply
Running under DOS.!! after will use a batch file.

NetRock · 06-22-2010, 08:01 AM

Under the DOS prompt this would work perfectly.

Quote:

echo host| sed 's/.$//g'

But this one:

Quote:

set param=`echo host| sed 's/.$//g'`

when i do echo param i get parama
this does not work~~!!!! any idea???

thank you for your help,

grail · 06-22-2010, 08:08 AM

So I know we are all probably a little lost seeing this is a linux site and not windows, but you are putting your newly created variable in between percentages?

yes??

Code:

set param=`echo host| sed 's/.$//g'`

echo %param%

This is only a guess at the issue I am afraid

NetRock · 06-22-2010, 08:33 AM

Good day grail,

you are right about linux site.... but i am using both to get the max. out of the two worlds. i want to avoid LONG Batch files by using the POWER of Linux.

Thank you again for your help. i will look for the code, once have it, will post it here.

Cheers...

NetRock · 06-22-2010, 10:51 AM

Here is the solution for the ones who are interested:

Quote:

echo %host%|sed s/.$//g >clus.txt
set /p host= < clus.txt

so we have to send it to a file and set it after.

grail · 06-22-2010, 07:48 PM

Quote:

so we have to send it to a file and set it after.

So not to be too narky, but just another illustration of the serious limitations of windblows .... yet again ... LOL

NetRock · 06-22-2010, 11:29 PM

WindBlows ...... interesting Truth!!! nice

ghostdog74 · 06-23-2010, 12:05 AM

with Windows, you don't have to create a temporary file just to store your result. Use the venerable for loop. something like this

Code:

for /F %%a ( echo %host% | sed ...) do (
  set var=%%a
)

konsolebox · 06-23-2010, 12:07 AM

windoze: echo %VAR:~0,-1%