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Regular Expression

I am trying to build a regular expression that will match the following:

http://www.linkedin.com/[a-zA-Z0-9]+
(the above URL followed by anything on the site)

Could someone point me in the right direction?

Thanks!

show an actual example of the input file you are parsing. basically, there is no need for a regular expression. the general logic can be:

Code:

if "http://" in string

What utility are you using? Depending on the context, you may already have it....

You can also use:
http://www.linkedin.com/.*

Quote:

Originally Posted by 0.o (Post 3566812)

you want to get what's after 'http://www.linkedin.com/'?
if you're parsing an html file and you want
to retrieve this info from the hyperlinks found in file.html

sed 's?href=[^ >]*?\n&\n?g' file.html | grep -i 'href=' | \
grep 'http://www\.linkedin\.com' | \
sed 's?^.*http://www\.linkedin\.com/$[^'" \t>]*$.*$?\1?' | \
sort -u

does that answer your question?