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Old 06-16-2004, 01:05 AM   #1
poeta_boy
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Regular Expresions on C++


Hi!

is there such a thing as regular expresions and their evaluations in C++?

like finding substrings and all

Thanks a lot!!

poeta
 
Old 06-16-2004, 02:58 AM   #2
maercin
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Regular expressions are not part of C++ standard. You have to use a library to do any regular expressions magic. Here is one worth taking a look at:

Boost regex library
 
Old 06-16-2004, 03:01 AM   #3
Mohsen
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There is nothing builtin C/C++ functions or libraries for matching regex offered by ANSI, but you may find lots of libraries on the Internet. Just make a google seasrch .
 
Old 06-16-2004, 10:44 AM   #4
Hko
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Quote:
There is nothing builtin C/C++ functions or libraries for matching regex offered by ANSI
Not by ANSI I assume. But in the GNU C libs and POSIX there is. So on Linux it's readily available.

See "man regcomp".

Last edited by Hko; 06-16-2004 at 10:47 AM.
 
Old 06-17-2004, 12:07 AM   #5
poeta_boy
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thanks a lot !!! I've downloaded Boost Regex and it seems to be working ok........ just a question........... I'm very shy about asking it.... what does it mean when a method has parameters separated by | pipe?

void method (param | param)

a really newbie question but I haven't used it before!!! now that I using this regex (I was reading the files it has) and some openGL I noticed this... please help!

Thanks
 
Old 06-17-2004, 04:34 AM   #6
maercin
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In c++ the '|' character stands for bitwise inclusive or operator. Its operands can be integral or enumeration types (the usual arithmetic conversions are applied). For example 3 | 5 = 7

To get the result convert the operands to binary form and OR each bit individually:

011
101
----
111

Here is C++ code to demonstrate this:

Code:
#include<iostream>

int main() {
    std::cout << (3|5) << std::endl;

    return 0;
}
 
Old 06-17-2004, 06:07 AM   #7
llama_meme
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In more practical terms, the | operator is often used to combine boolean options. So foo(X | Y | Z) means call foo with the option X, Y and Z all set. This still works in terms of bitwise OR &mdash; the various options are constant integers with all the bits except for a single 1 set to 0.

Alex
 
Old 06-18-2004, 12:00 AM   #8
poeta_boy
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thanks everyone! boost regex works like a charm!! strongly recommended

Thanks
 
  


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