ok i want to read 200kb of raw data.....
and put it in to memory as a real number
and i want access to that number so ican do calculations on it
like half it find the power and that lot

Not going to happen without a special library to perform calculations with numbers of that magnitude, and even then, it will take a LONG time to perform mathematical calculations with numbers like that.

i just want to read 200kb of data (hexed) and put it in to decimal...which would result ina file that is 300kb
now i want to read that 300kb in to memory and access it as a number..so i can perform division on it
so i can find the power i need to get close to that file

200kb of hex? That would be 100kb of raw (binary) data. Why do you need to find that power?

You'll need to write a program that uses the GNU Multiple Precision library, or something similar, to perform this math. If you intend to use it as an integer, you can use mpz_set_str(mpz_t val,char *string) with the value prepended with 0x and terminated in a null. You can use getc() to create this string in memory.

ok i dont care about programming
i just want to know the lines of code to read raw data one byte a time..convert to dec and write the resulting code in to memory
and that give em a solution so i can access that number via a varible

I am not your personal programmer. Just to put this in memory would be several dozen lines of code. I will outline them here, for your benefit:
val now contains the value you were looking for. That code is just a skeleton, you'll obviously need some error checking and other work.

char *buf=(char *)malloc(200*1024+1);
unsigned int i=0;
FILE *fp=fopen("/path/to/file","r");
mpz_t val;

while(!feof(fp)){
buf[i++]=fgetc(fp);
}
fclose(fp);
fp=NULL;
buf[i]=0;

mpz_init(val);
mpz_set_str(val,buf,16);

so if i did newval = val / 2 (i know that not probably right) but that would give me a val in newval which is half the size....which that all i would have to do is this newval x 2 = val

so thats it....i dont actually get any help aprt from some code that i dont know what it is for..i assume it is either C or C++
but dunno if the idea of just halving value will result in it being smaller in generally no mater what it is

What kind of help do you want? I pointed you to the proper libraries and functions, and gave you sample code to read in the value. With that value, you'll have to use the GNU MP library's functions to manipulate it.

smaller in size or in value ?

just say u could make a number turn in to a base that supported 300k....i could represent any 300kb number with very few numbers yes......ok i want to know if i could just tell u any number in sequence.....and u could work it out...e.g. 3000 digit ..now u tell me what info u need to determine a number by cubing ..

How could you represent and 300 kb number with very few numbers? I'm a bit confused.

Ok first your question is really badly written.

1. you dont ask what programming language you need help in so we assumed it was C because of its ablity to manipulate memory easly.


the code written here is C if im mistaken somone correct me please. Thats a nice bit of code and does answer your question. It however is not compleate (not my words but the words of the author) and should not be used in its pure form but compleated with proper error checking.


now even if 300kb of raw data doesent seam like alot as far as modern space on computers go it acutally is a huge amount of data when working with raw binary data in programming.


please rewrite your question with some details on what you are trying to accomplish and we will be happy to assist you in any way.

Im not trying to be mean or anything but your question is kinda just thrown out there so you get erratic results.

ok u use 16 to represent anynumber in binary .......if thats is yes
then how many numbers is it actually representing if i use base 32

Base 32? That would be 5 bits/character, so 300k would become 5/8 of that, or about 187k.

Exvor, you are correct in all parts of what you said. I'm glad to know I wasn't just so confusing that nobody could understand me.