python regexp?

dave201 · 05-06-2008, 01:33 PM

greetings and such.

im trying to figure this regex thing out in python but am having a bit of trouble. down below on the os.path line, im trying to find any files in that directory that end in ".lock"

The below code doesn't work, anyone know how to get this done?

Code:

import os
import re

if os.path.exists('/home/dave/code/*.lock) == True:
        print "stuff is locked"
else:
        print "not locked"

rocket357 · 05-06-2008, 02:49 PM

glob would work better, but if you really wanted to go the regex route, you could do something like this:

Code:

import os, re
# Create a regular expression object to match against
lock_re = re.compile('([.]*.lock)')

# grab a list of filenames in /home/dave/code
for filename in os.listdir('/home/dave/code'):
    # check to see if the filename matches the regex
    # this step could also be done like such:
    # if filename.endswith('.lock'):
    lockMatch = lock_re.search(filename)
    if lockMatch is not None:
        print "stuff is locked"
        break

The same with glob would look something like this:

Code:

import glob

# check the current working directory...
# can use os.chdir to check a dir other than the cwd
filelist = glob.glob('*.lock')

if len(filelist) > 0:
    print "stuff is locked"
else:
    print "not locked"

glob would also be a better solution since you could then iterate over the filelist to see what exactly is locked.

dave201 · 05-06-2008, 02:50 PM

hero award for rocket357

thanks!

Ome_Roel · 05-06-2008, 03:05 PM

Goodevening, i found this on the pythonDOTorg site:

Code:

import fnmatch
import os

for file in os.listdir('.'):
    if fnmatch.fnmatch(file, '*.txt'):
        print file

Yours kindly Roel