Python function-string

Zero4 · 04-25-2014, 09:53 PM

Hi
I am learning Python and I am writing an function that takes a list as a parameter and returns a string like so:

List: item1, item2, item3, .......item24

Here is what my code looks like:

Code:

#!/usr/bin/python3

def to_string(alist):
	s=''
	for i in alist:
		s=s+i
		return s

alist=['123','456','789','101']
result=to_string(alist)
print(alist)

This code outputs 123456789101 and i have played with it a lot and got
many different looking strings.
Thanks in advance

sycamorex · 04-25-2014, 10:37 PM

The code, as it is above, correctly outputs an unmodified version of the list 'alist'.

Can you clarify your question please? Do you want it to output:

1, 2, 3, 4, 5, 6, ....?

If so you could use:

Code:

def to_str(alist):
    s = ''
    for i in alist:
        for x in i:
            s += x
    return ', '.join(s)

alist=['123','456','789','101']
result=to_str(alist)
print(result)

or simply:

Code:

def to_str2(alist):
        return ', '.join(''.join(alist))

alist=['123','456','789','101']
result=to_str2(alist)
print(result)

Zero4 · 04-25-2014, 11:04 PM

Thanks sycamorex
Yes i do want it to output 1, 2, 3, 4, 5, 6 but without the comma at the end of the last item. And the "List:" at the front.
That's the tricky bit, I can't make work, getting it to output the List at the front and no comma at the end.

sycamorex · 04-25-2014, 11:10 PM

Quote:

Originally Posted by Zero4

Thanks sycamorex
Yes i do want it to output 1, 2, 3, 4, 5, 6 but without the comma at the end of the last item. And the "List:" at the front.
That's the tricky bit, I can't make work, getting it to output the List at the front and no comma at the end.

Code:

def to_str2(alist):
        return 'List: ' + ', '.join(''.join(alist))

alist=['123','456','789','101']
result=to_str2(alist)
print(result)

Wouldn't that do it?