Problem with shell script using a variable from a unix command.

abefroman · 05-10-2006, 02:11 PM

It is not putting the number only in $swap.

How can I get it to store the 4th number only from free -m |grep Swap?

$swap=`free -m |grep Swap | awk {'print $4'}`;
if($swap < 100){
print "swap low";
}

Thanks in advance!

gilead · 05-10-2006, 02:14 PM

Don't put the '$' in front of the variable name when you're assigning to it. For example, the following works on my PC:

Code:

SWAP=`free -m | grep Swap | awk {'print $4'}`
echo $SWAP