[SOLVED] problem with sed

sang_froid · 05-22-2011, 10:22 AM

Hi,

I am just trying to run the following piece of awk code. But it doesn't print anything...

where I am doing wrong ?

Quote:

[root@moon]# more script
#!/bin/awk -f
BEGIN {

# Print the squares from 1 to 10 the first way

i=1;
while (i <= 10) {
printf "\nThe square of ", i, " is ", i*i;
i = i+1;
}

}
[root@moon]# ./script

The square of
The square of
The square of
The square of
The square of
The square of
The square of
The square of
The square of
The square of

grail · 05-22-2011, 10:25 AM

Well firstly its an awk script and not sed!!

Secondly you need to lookup how to use printf, in general even though it is the same for this case.

druuna · 05-22-2011, 10:29 AM

Hi,

Or change : printf "\nThe square of ", i, " is ", i*i; to print "The square of ", i, " is ", i*i;

Hope this helps.

sang_froid · 05-22-2011, 10:33 AM

Got it fixed...

Quote:

Originally Posted by sang_froid

Hi,

I am just trying to run the following piece of awk code. But it doesn't print anything...

where I am doing wrong ?

grail · 05-22-2011, 10:47 AM

Please mark as SOLVED.

Reuti · 05-23-2011, 03:09 PM

Maybe to explain: printf needs some formatting place holders like %d to print the arguments in the supplied list. I.e.

Code:

printf "\nThe square of %d%s%d", i, " is ", i*i;

will do it too.