Problem with AWK in a BASH script

geek_man · 01-20-2008, 01:41 PM

Hi!

I am writing a bash script to rename my songs. But as some song's names have spaces I had to use awk, but now I have a problem.
Here is my script:

Code:

#!/bin/bash 

MINPARAMS=4
AWKSCRIPT=' { gsub(" ", "\\ "); print | "mv"} '

if [ $# != "$MINPARAMS" ]
then
	echo "This script needs at least 4 parameters."
	echo "Use: "
	echo "rename_song artist_name disc_name song_name song_to_rename"
	exit
else
	name=$1_$2_$3
	echo $4 $name | awk "$AWKSCRIPT" 
fi

It should work fine, but there is a problem: I am using gsub to scape the spaces in the name, but it leaves a \ at the end of the name and I have to delete this \ for mv to work fine. I know that I can do it in this form:
sub(/\/+$/, ""), but it doesn't work. I am not an expert in AWK, if there is another way to do it, please tell me.

Thanks.

ilikejam · 01-20-2008, 01:47 PM

You shouldn't have to replace the " "s with "\ "s - just quote the string when you run mv, e.g.

$ mv "track 3.mp3" "Orbital - Belfast.mp3"

Dave

geek_man · 01-20-2008, 04:19 PM

Quote:

Originally Posted by ilikejam

You shouldn't have to replace the " "s with "\ "s - just quote the string when you run mv, e.g.

$ mv "track 3.mp3" "Orbital - Belfast.mp3"

Dave

Yes, I know it works perfectly when you run it directly in the command line, but not when you do in a bash script. Is there a way to escape the quotes in a bash script?

Here is my code:

Code:

#!/bin/bash 

MINPARAMS=4

if [ $# != "$MINPARAMS" ]
then
	echo "This script needs at least 4 parameters."
	echo "Use: "
	echo "rename_song artist_name disc_name song_name song_to_rename"
	exit
else
	name_new="$1_$2_$3"
	name_old="$4"
	mv "'$name_old'" "'$name_new'"
fi

Thanks.

ilikejam · 01-20-2008, 05:00 PM

It's just:

mv "$name_old" "$name_new"

Dave

geek_man · 01-20-2008, 07:16 PM

Quote:

Originally Posted by ilikejam

It's just:

mv "$name_old" "$name_new"

Dave

Now it works fine, thanks. Sometimes the solution is easy, but we think it is really difficult.