[SOLVED] Printf: giving "001 002 003 004 006.... 150" in a single line dash command?

Xeratul · 01-15-2011, 10:18 PM

Hello,

I am intended to simply make printf give "001 002 003 004 006.... 150" but with the single command line of SH (dash) ... not easy ...

well a non working solution..

Code:

tucholsky:~$ seq 1 1 150 | sed 's/\([0-9]\+\).*/\1/g' | tr '\n' ' '
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150

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For the geeks, which distro/version is it, based on the code above

grail · 01-15-2011, 10:54 PM

Maybe something like:

Code:

for i in $(seq 1 1 150);do printf "%03d " $i;done

crts · 01-15-2011, 11:49 PM

Quote:

Originally Posted by grail

Maybe something like:

Code:

for i in $(seq 1 1 150);do printf "%03d " $i;done

Hi grail,

nice solution. It can be even shortened to just

Code:

printf "%03d " $(seq 1 150)

grail · 01-15-2011, 11:52 PM

Cheers crts ... wasn't aware it would feed the items singularly to printf.

jschiwal · 01-16-2011, 12:23 AM

Does your version of seq have the -w and -s options? If so, using -w will give you the leading zeros. Using -s' ' will use spaces to separate numbers instead of newlines.

Xeratul · 01-16-2011, 04:02 AM

wow, thank you !! It is gorgeously short and effective

I am sorry that I forgot such elementary thing with printf

grail · 01-16-2011, 07:00 AM

Once you have a solution please mark as SOLVED