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Linh	08-13-2003 05:55 PM

Print statement never executed

Print statement never executed

./getdata long

=========================================

Code:

#include <stdio.h>  

#include <stdlib.h> 



char *progam_name;

char *parameter1;



main(argc, argv)

  int argc;

  char *argv[];

 {

    progam_name = argv[0];

    parameter1  = argv[1];



    if (argc < 2)

      do_process_1();

    else

      if (argc == 2 && parameter1 == "long")

PROBLEM -->>          printf ("parameter1 = %s\n", parameter1);

 }

kev82

08-13-2003 06:14 PM

actually the problem is the line above, you cant compare strings like that, refer to this thread http://www.linuxquestions.org/questi...590#post422590 the required modification is

if( argc == 2 && !strcmp(parameter1, "long"))

strcmp is defined in string.h

Linh	08-14-2003 12:28 PM

to kev82

Hi. the statement below
if( argc == 2 && !strcmp(parameter1, "long"))

When there is two argument and parameter1 is equal to long. That is what I mean. An ! (exclamation) means parameter1 is not equal to long, when in fact it is.

When I used an ! , the condition is met.
When I leave out an !, the condition is never met.

Please explain. An ! means it should not equal, when in this case it is.

kev82

08-14-2003 12:46 PM

as the man page states, strcmp returns 0 if the strings are equal, non-zero otherwise. so !strcmp returns 0 if there not equal, and non-zero if they are equal.

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