/*This program finds the maximum of the expression:
y=x^3 - 14x^2 + 56x - 64
-2<x<8

define the two integer values that we'll be using
*/
  define(a1, 4)
  define(a2, 14)


/*Variables x and y are stored in %11 and %12. Result store in 10*/
  define(r_r, 10)
  define(x_r, 11)
  define(y_r, 12)

  .global main
main:
  save %sp, -96 %sp

  clr %x_r                !initialize x to zero
  mov -2, %x_r
  .global loop
/*
To simplify, the problem can also be written as:
x(x-14(x+4))
or
x^x - 14*x * x+4
*/
loop:

  /* x+4 */
  add       %x_r, a1, %o3
  mov       %x_r, %o2
  call      .mul
  nop
  /*  *(x*14) */
  mov       %x_r, %02
  call      .mul
  nop
  mov       a2, %02
  call      .mul
  nop
  /* Now move the answer to a different register, clear %o0 for the second
     part of the equation. */
  mov       %o0, %o2
  clr       %o0
  mov       %x_r, %o0
  mov       %x_r, %o1
  call      .mul
  nop
  sub       %o0, %o3, %o0
  mov       %o0, %y_r

  /*do..while condition. Check if the max for this value of x is greater than
    anything before it */
  cmp       %y_r, %10
  ble       next
  nop
  mov       %o0 %10
next:
  clr       %o0
  clr       %01
  clr       %02
  clr       %03
  add       %x_r, 1, %x_r

  cmp       %x_r, 8
  b1        loop
  mov       %y_r, %o0

  mov       1, %g1
  ta        0