hi,


this is driving me up the wall

i am typing to make an if statement that will work out if a certain value is given from a database then it will perform a certain task

for example: if the database says the value is 1 then it changes the html to a different button is loaded if its 2 then an extra button is loaded and so on

every time i issue the statement i get back parse errror on line x
i have even looked it up and i cannot find the answer, here is what i am typing

if($lalala == '1'){
dothis();
}

and it fails every time

any ideas??

A debugging trick I use when I can't for the life of me find the problem is to comment out the if($lalala section. Right above it, do something like "echo $lalala" so you can see what value is being compared.

As for the code shown, looks fine to me.

try double quotes. may still fail, but try it anyway.


also, where was $lalala declared. i had that problem because i thought some variables were global but werent

Even if $lalala isn't declared, it shouldn't give you a parse error, it will just return false.

Could you post some more code, it could be that the line before the if statement is causing you trouble.

What's the output of the sql query? I can't see anything wrong with the if. AFAIK, don't need to use quotes when the value of the variable is numeric.

regards
theN