PHP: fgets works like a readline in 5.2.x but not in 5.1.2

eantoranz · 07-20-2007, 02:53 PM

If I use fgets on STDIN in php in version 5.2.3 (ubuntu gutsy... but so did in edgy and feisty), it waits for a line of input before proceding, but in version 5.1.2 it just goes ahead without stopping for input (not even a character). How can I avoid that?

Follow this example:

Code:

<?
if (! defined(STDIN)) {
        define("STDIN", fopen("php://stdin", "r"));
}
while (!feof(STDIN)) {
        $line = trim(fgets(STDIN));
        $fields = explode(' ', $line);
        $username = rawurldecode($fields[0]); //1738
        $password = rawurldecode($fields[1]); //1738
        if ($username == 'hello' 
            and $password == 'world') {
                fwrite(STDOUT, "OK\n");
        } else if ($username == 'fo'
            and $password == 'bar') {
                fwrite(STDOUT, "OK\n");
        } else {
                // failed miserably
                fwrite(STDOUT, "ERR\n");
        }
}
?>

How can I force it to wait for a line of input? Can I just use readline()?

eantoranz · 07-20-2007, 02:56 PM

I just tried with readline and the function is not defined... I guess there must be a process to make it available. :-S As I said before... is there a wait to force fgets to wait for a whole line of input?

eantoranz · 07-20-2007, 03:20 PM

Solved it!

The problem is the define call. I have the fopen() right in the define, and it fails that way. If you do the fopen and save the result in a temporary variable, it works.

Try with this:

Code:

if (! defined(STDIN)) {
    $temp = fopen("php://stdin", "r");
    define("STDIN", $temp);
}

It worked with version 5.1.2 that way.

It worked with 5.2.3 the original way... I guess it's a bug in 5.1.2