from a perl tutorial i have been looking at i am puzzled why i get the results:

[chijtska@chijtska perl]$ perl operator.pl
Two $nums are 10 * 2 and adding one to $var makes Perl++
Two $nums are 20 and adding one to $var makes Perl

here of course are the lines of code:

$num=10;
print "Two \$nums are $num * 2 and adding one to \$var makes $var++\n";
print "Two \$nums are ", $num * 2," and adding one to \$var makes ",
$var++,"\n";

why did $var come out as Perl++ instead of Perm? Yes, I have read the section in the tutorial about it but it doesnt give a satisfactory answer...

thanks

huh? the first one is printed as perl++ as ++ is just a text strign in that case... i don't follow what you mean..

nice to see a questions actually abuot programming on this forum for once...

the reason i ask is that when you designate $var++ (when $var="perl") youre supposed to get "perm", right?

sorry i wasnt clear

shoot!--- nevermind... i get it... $var was never given the value "perl"... ok i was making too big a deal out of it