operators

linuxanswer · 12-14-2003, 03:29 PM

#include <stdio.h>

int main() {

int set;
int can = 4;

int += can;
printf("d", set);

return 0;

}

why this code give me output 268336224?

linuxanswer · 12-14-2003, 03:30 PM

sorry
int += can; NO

this 's the correct

set += can;

wapcaplet · 12-14-2003, 03:31 PM

Because the variable 'set' is not initialized; it's just using whatever value was left-over in memory.

Also, if you are wanting to print out the value of set, the printf statement should use '%d' instead of 'd'.

Tesl · 12-14-2003, 06:09 PM

you need to initalize 'set' first

Code:

#include <stdio.h>

int main() {

int set = 0;
int can = 4;

int += can;
printf("d", set);

return 0;

}

If you dont initialise variables first, they will just contain garbage values