[SOLVED] Need some shelling scripting help....

ProtoformX · 10-01-2010, 07:02 AM

I'm trying to retrieve a single string or value from /proc/cpuinfo, but when I try to extract the model (not the model name) the model name comes with it, also it likes to print it twice...

Code:

 model="`cat /proc/cpuinfo | grep model | cut -d: -f2  | cut -c1-3`"
echo $model

What am I doing wrong?

All i want this to do is spit out the model number once. (I need to pass it to another script)

vonbiber · 10-01-2010, 07:17 AM

Code:

model=$(cat /proc/cpuinfo | grep model | grep -v name | sed 's/^[^:]*: //')

should do the job

druuna · 10-01-2010, 07:17 AM

Hi,

model=$(awk '/model / { print $3}' /proc/cpuinfo)

That is not a space after /model but a tab (ctrl-v + tab).

Hope this helps.

GrapefruiTgirl · 10-01-2010, 07:20 AM

It is printing it twice, I suspect because you have a dual core CPU (or two CPU's by some means).

Maybe this will give you an idea (just tossed together quick!):

Code:

awk '/^model[[:space:]]+:/{print $NF; exit}' /proc/cpuinfo

kurumi · 10-01-2010, 07:48 AM

Code:

$ ruby -F":" -ane 'if $F[0][/model\s+(?!name)/] then puts $F[1];exit end' /proc/cpuinfo

grail · 10-01-2010, 11:03 AM

I like the awk and ruby, but figure sed should get a go:

Code:

sed -r -n '/model\t/{s/[^0-9]+//p;q}' /proc/cpuinfo

GrapefruiTgirl · 10-01-2010, 11:14 AM

Hey wait, where's a plain bash version?

Code:

while read one two three; do if [ "$one" = "model" ]; then echo $three && break; fi done < /proc/cpuinfo

EDIT:
Seeing the newer posts further down made me realize that this code will also fail if someone's /proc/cpuinfo file produces "model name" before "model", so here's a modification, with a safeguard to ensure that only the "model" line will be given:

Code:

while read one two three; do [ "$one" = "model" -a "$two" = ":" ] && echo $three && break; done < /proc/cpuinfo

ArfaSmif · 10-01-2010, 07:32 PM

grep -m 1 model

will give you one instance of the match

grail · 10-02-2010, 12:51 AM

@ArfaSmif - how does your example provide the number at the end of the line?
What happens if "model name" comes first?

ArfaSmif · 10-02-2010, 09:23 PM

Quote:

Originally Posted by grail

@ArfaSmif - how does your example provide the number at the end of the line?
What happens if "model name" comes first?

yes only true of model comes first which it does on my system and if it doesn't then :-

cat /proc/cpuinfo |grep -v "model name" | grep -m 1 model

etc

grail · 10-03-2010, 01:17 AM

But you still have not returned what the OP requested

ArfaSmif · 10-03-2010, 04:15 AM

Quote:

Originally Posted by grail

But you still have not returned what the OP requested

I only wanted to show them how to use grep.

So you can be happy, here goes :-

model=`cat /proc/cpuinfo |grep -v "model name" | grep -m 1 model | cut -d: -f2`

catkin · 10-03-2010, 05:00 AM

Quote:

Originally Posted by ArfaSmif

I only wanted to show them how to use grep.

So you can be happy, here goes :-

model=`cat /proc/cpuinfo |grep -v "model name" | grep -m 1 model | cut -d: -f2`

That gives " 107" on my system.

Here's a solution using bash parameter substitution

Code:

buf=$(cat /proc/cpuinfo); buf=${buf##*model name}; buf=${buf#*:}; echo ${buf%%$'\n'*}

It could be one step shorter if the number of spaces after "model name" and before ":" is taken as fixed or if extended pattern matching (extglob) is enabled.

EDIT: oops! I mis-read the thread and did not realise it was "model" not "model name" that is required.

EDIT2: second attempt:

Code:

shopt -s extglob
buf=$(cat /proc/cpuinfo); buf=${buf##*model+([$'\t' ]): }; echo "${buf%%$'\n'*}"

ghostdog74 · 10-03-2010, 06:12 AM

Quote:

Originally Posted by catkin

EDIT2: second attempt:

Code:

shopt -s extglob
buf=$(cat /proc/cpuinfo); buf=${buf##*model+([$'\t' ]): }; echo "${buf%%$'\n'*}"

Code:

buf=$(</proc/cpuinfo)

ArfaSmif · 10-03-2010, 06:32 AM

@catkin, looks like /proc/cpuinfo produces very different output for different cpus etc. I have an AMD Athlon(tm) II X4 630 Processor and my bash script works ok for my cpu. My output is "5" which is what I thought ProtoformX was trying to get.