[SOLVED] Multipal line edited using sed, how to make sed specific

coolpraz · 01-05-2013, 06:04 AM

Hi,
im wirting the bash script to change the text from configuration file of httpd.conf, In a configuration file there are many similar lines(likely) to configuration. when i change the text using sed its change the other section tooo. how to overcome form this .
eg: -

Code:

$ cat test.txt

# Timeout: The number of seconds before receives and sends time out.
Timeout 60
#KeepAliveTimeout:
KeepAliveTimeout 15

I used this code to change

Code:

sed -i '/^#/!s/Timeout .*/Timeout 45/' test.txt

When i execute this its change both Timeout 60 and KeepAliveTimeout 15 to Timeout 45 and KeepAliveTimeout 45, However i want to change only value of Timeout 60 not the KeepAliveTimeout 15

whizje · 01-05-2013, 06:53 AM

Code:

bash-4.2$ cat test.txt

# Timeout: The number of seconds before receives and sends time out.
Timeout 60
#KeepAliveTimeout:
KeepAliveTimeout 15
bash-4.2$ sed -i 's/Timeout 60/Timeout 45/' test.txt
bash-4.2$ cat test.txt

# Timeout: The number of seconds before receives and sends time out.
Timeout 45
#KeepAliveTimeout:
KeepAliveTimeout 15
bash-4.2$

millgates · 01-05-2013, 08:48 AM

Code:

sed -i '/^#/!s/\bTimeout .*/Timeout 45/' test.txt

\b is a metacharacter that matches a "word boundary".

coolpraz · 01-05-2013, 01:12 PM

Quote:

Originally Posted by whizje

Code:

bash-4.2$ cat test.txt

# Timeout: The number of seconds before receives and sends time out.
Timeout 60
#KeepAliveTimeout:
KeepAliveTimeout 15
bash-4.2$ sed -i 's/Timeout 60/Timeout 45/' test.txt
bash-4.2$ cat test.txt

# Timeout: The number of seconds before receives and sends time out.
Timeout 45
#KeepAliveTimeout:
KeepAliveTimeout 15
bash-4.2$

Thanx whizje but im using wild card .*, so that whatever time is set its must change that time to 45 sec. I really appricate your help, Thank you whizje

coolpraz · 01-05-2013, 01:14 PM

Quote:

Originally Posted by millgates

Code:

sed -i '/^#/!s/\bTimeout .*/Timeout 45/' test.txt

\b is a metacharacter that matches a "word boundary".

Thank you millgates for solving my problem this excatly work for me thank you very much