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Old 06-17-2009, 12:43 AM   #1
fcdev
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Registered: Sep 2005
Posts: 47

Rep: Reputation: 15
Javascript - trouble using array with getElementById


I have an array of select boxes in a web page, named:
item0
item1
...
item9

I need to fill these boxes with a list of options. The same list goes into each select box. I have tried to do this with arrays but my lists appear empty. When I don't use arrays, things work ...

I'll cut the code down a bit to save space ...

Here is the working code:
var id
var name
var s0
var s1
var s2

// Here I'm using PHP to generate some of the code for me
for ($i=0; $i<9; $i++)
{ echo "s$i=document.getElementById(\"item$j\")\n";
}
// querydb is a wrapper that queries MYSQL and reports errors
$query = querydb("select id, name from items");
while ($data = mysql_fetch_array($query))
{ echo "id = \"$data[0]\"\n";
echo "name=\"$data[1]\"\n";
for ($i=0; $i<9; $i++)
echo "s$i.add(new Option(name, id), null)\n";
}

// -----------------------------
Forgive me if that code has come logic errors caused by cutting it down for this site ... the actual code is considerably more complex, and I only want to show the relevant pieces.

Now ... Here's the same code using arrays which DOESN't work ...

var id
var name
var s = new array[9]

// Here I'm using PHP to generate some of the code for me
for ($i=0; $i<9; $i++)
{ echo "s[$i]=document.getElementById(\"item$j\")\n";
}
// querydb is a wrapper that queries MYSQL and reports errors
$query = querydb("select id, name from items");
while ($data = mysql_fetch_array($query))
{ echo "id = \"$data[0]\"\n";
echo "name=\"$data[1]\"\n";
for ($i=0; $i<9; $i++)
echo "s[$i].add(new Option(name, id), null)\n";
}

// -----------------------------

What it looks like what's happening is the s[$i].add part is the problem, my assumption is that it's trying to call a array.add() function, instead of document.getElementByID(...).add function.
Anyone know how I could fix this?

Thanks
 
Old 06-17-2009, 03:43 AM   #2
Guttorm
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Registered: Dec 2003
Location: Trondheim, Norway
Distribution: Debian and Ubuntu
Posts: 1,295

Rep: Reputation: 335Reputation: 335Reputation: 335Reputation: 335
PHP Code:
// Here I'm using PHP to generate some of the code for me
for ($i=0$i<9$i++)
{ echo 
"s[$i]=document.getElementById(\"item$j\")\n";

I don't know if this is just a typo, but the element you get is "item$j" - where is $j?

Also, isn't it easier to look at the HTML instead of the PHP? Does it make any Javascript errors?

Edit:
var s = new array[9]

This is also incorrect, try this instead:
var s = new Array(9);

Last edited by Guttorm; 06-17-2009 at 03:46 AM.
 
Old 06-17-2009, 11:36 PM   #3
fcdev
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Registered: Sep 2005
Posts: 47

Original Poster
Rep: Reputation: 15
Talking

Quote:
Originally Posted by Guttorm View Post
This is also incorrect, try this instead:
var s = new Array(9);
YES, that's it! Well, that's the problem you get when you are writing a program using 4 different languages ... you make a stupid mistake like that Although, I'm kind of baffled as to why the mistake wasn't reported in the exception handler, but who cares, the code works now ... Thank you very much for that.

As for your other statements ... The $j wasn't a typo - but I accidently left out the calculation of $j, and yes, I suppose I should have pasted the code generated by PHP instead of pasting the PHP code.
 
  


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