Initialization of a pointer in C-a question

xailer · 01-02-2004, 10:47 AM

hi

I came accross an example where pointer is initialised directly from integer:

int x=1;
int *px=x; //notice it doesn't use &x
printf("%d",(int)px);

What is happening here ? How can pointer get address from x ?
And if you can get value of x by just casting poinetr to int ,that would mean that px saved a value of an integer and not its address .

And what is the benefit of doing it like that ? Is assigment any faster ?

thank you

bye

luxitan · 01-02-2004, 11:13 AM

the pointer aint getting the address of x, it's getting it's value

its excly the same of

char px=x;
printf("%d",(int)px);

doensn't matter the type of px you're just casting

>> And what is the benefit of doing it like that ?

none, just more confusing to who reads the code

nibbler · 01-02-2004, 11:42 AM

i think gcc wouldn't allow that

xailer · 01-02-2004, 11:46 AM

thank you for your help

bye

luxitan · 01-02-2004, 12:57 PM

Quote:

Originally posted by nibbler
i think gcc wouldn't allow that

it will give a warning but it's valid