LinuxQuestions.org - incrementing variable in an until loop

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incrementing variable in an until loop

What's wrong with this?

Code:

x=1;

until $x=30;

do

grep blah blah blah blah blah...;

sed blah blah blah blah;

x=$x+1;

done;

Becuase this is what I get...

Code:

/bin/getphone: line 6: 1=30: command not found

/bin/getphone: line 6: 1+1=30: command not found

/bin/getphone: line 6: 1+1+1=30: command not found

/bin/getphone: line 6: 1+1+1+1=30: command not found

/bin/getphone: line 6: 1+1+1+1+1=30: command not found

/bin/getphone: line 6: 1+1+1+1+1+1=30: command not found

/bin/getphone: line 6: 1+1+1+1+1+1+1=30: command not found

I'm trying to fix a "script" from another thread, and I can't figure out how to run the commands within the loop 30 times and stop and exit...

Greatly appreciate any assistance...

Jeff

You need to use let to do arithmetic in bash:

let "x = $x + 1"

That "until" syntax doesn't look right either. Try until [ $x -eq 30 ]; do

Excellent!

Thank you!!

Now for the next problem....new thread...