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Old 03-05-2006, 01:50 PM   #1
Registered: Sep 2004
Location: Old York, North Yorks.
Distribution: Debian 7 (mainly)
Posts: 653

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If statement doesn't work properly in JavaScript

I'm just learning to use JavaScript, and at the moment I'm working on writing a program to play noughts-and-crosses. It will use a grid of html buttons within a form (name/id="board") as the playing board. The onclick property of each of these buttons calls a function called Click, passing its element number within the form (held in the variable btn).

I was playing around with controlling the value of these buttons, depending on their existing value. I tried using the following seies of if statements, but it does not work (the first option is always executed - setting the button's value to "X"):
var checkit = document.forms["board"].elements[btn].value
	if(checkit=" ")
	else if(checkit="X")
	else if(checkit="0")
		{document.forms["board"].elements[btn].value=" ";}
However, the equivalent switch statement works perfectly, allowing me to cycle through the 3 values:
		case " ":
		case "X":
		case "0":
			document.forms["board"].elements[btn].value=" ";
Can anyone see what I may be doing wrong? Or is it a known problem?

I'm using SuSE 10.0 with Gnome 2.12, and I've tested this in both Firefox 1.5 and Konqueror 3.4.2.


Last edited by Robhogg; 03-05-2006 at 02:21 PM.
Old 03-05-2006, 03:03 PM   #2
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in you if statement you want to use == to test.. by using only = you are assigning instead of testing and trashing your vars..
Old 03-05-2006, 03:30 PM   #3
Registered: Sep 2004
Location: Old York, North Yorks.
Distribution: Debian 7 (mainly)
Posts: 653

Original Poster
Rep: Reputation: 97

Paint me yellow, and call me Homer

I should have spotted that. Thanks.



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