I can offer my help
Hello!
At the moment I have a lot of free time and I want to help some good open source project which is going to make more people to use linux. I have about 2 years experience of C++ programing, mainly on Borland C++ Builder and MSVC. I installed Linux about half year ago. I also can learn a new language if it is needed. I can go to Source Forge and ask to join some project, but first I want to get some advice from you. Thanks |
There are plenty of orphaned projects on SF. Also, there are hundreds of projects looking for testers/debuggers.
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The thing is that I want not only to help but also not to waste my time.
Source Forge is good but, for me it's hard to tell good projects from projects which are never going to be complited... |
That's really up to you to decide. Just because something is free software doesn't necessarily mean it shouldn't have a target market. I'm sure the last thing the world needs is 'yet another image convertor', but I'd give my left ball for a better installation/setup tool for debian.
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Check out
http://unmaintained.sourceforge.net/ They have piles of unmaintained projects some of which were very promising and are really interesting. Find something that interests you to code or something that you need/want. |
find something that bugs you. Write a program to fix it.
*bing* *bing* *bing* a multitued of ideas there! titanium_geek |
Hey could anyone help me fix my error for this C progam that calculates the surface distance. It is showing some errors.
Thanks #include <stdio.h> #include <math.h> #include <string.h> #define RHO 6367 #define PI 3.141592654 void read_GPS(float *,float *,float *,char *); float convert_DD(float *, float *, float *); float calc_SphereCoord_lat( char *, float *); float calc_SphereCoord_long(char *, float *); float deg2rad(float *); float calc_3DCoord(float *, float *); float straight_D(float *, float *, float *, float *, float *, float *); int main(void) { float deg_lat_1, min_lat_1, sec_lat_1, deg_long_1, min_long_1, sec_long_1; float deg_lat_2, min_lat_2, sec_lat_2, deg_long_2, min_long_2, sec_long_2; float dec_deg_1, dec_deg_2, dec_deg_3, dec_deg_4; float rad_lat_1, rad_long_1, rad_lat_2, rad_long_2; float phi_lat_1, theta_long_1, phi_lat_2, theta_long_2; char s1[10], s2[10], s3[10], s4[10]; printf("Please enter co-ordinates in format of 123 45 30 North\n" ); printf("where 123 = Degrees 45 = minutes 30 = seconds and North = direction.\n"); printf("Please enter in lattitudinal co-ordinates for start point:\n"); read_GPS(起lat_1,&min_lat_1,&sec_lat_1,s1); dec_deg_1 = convert_DD(起lat_1,&min_lat_1,&sec_lat_1); rad_lat_1 = calc_SphereCoord_lat(s1, &dec_deg_1); phi_lat_1 = deg2rad(&rad_lat_1); printf("Please enter in longitudinal co-ordinates for start point:\n"); read_GPS(起long_1,&min_long_1,&sec_long_1,s2); dec_deg_2 = convert_DD(起long_1,&min_long_1,&sec_long_1); rad_long_1 = calc_SphereCoord_long(s2, &dec_deg_2); theta_long_1 = deg2rad(&rad_long_1); calc_3DCoord(&phi_lat_1, &theta_long_1); printf("Please enter lattitudinal co-ordinates for final destination:\n"); read_GPS(起lat_2,&min_lat_2,&sec_lat_2,s3); dec_deg_3 = convert_DD(起lat_2, &min_lat_2,&sec_lat_2); rad_lat_2 = calc_SphereCoord_lat(s3, &dec_deg_3); phi_lat_2 = deg2rad(&rad_lat_2); printf("Please enter longitudinal co-ordinates for final destination:\n"); read_GPS(起long_2,&min_long_2,&sec_long_2,s4); dec_deg_4 = convert_DD(起long_2,&min_long_2,&sec_long_2); rad_long_2 = calc_SphereCoord_long(s4, &dec_deg_4); theta_long_2 = deg2rad(&rad_long_2); calc_3DCoord(&phi_lat_2, &theta_long_2); printf("Degrees:%f \n Minutes: %f \n Seconds:%f \n Direction:%s\n", deg_lat_1, min_lat_1,sec_lat_1, s1); printf("%f %f %f %s\n", deg_long_1, min_long_1, sec_long_1,s2); printf("%f %f %f %s\n", deg_lat_2, min_lat_2, sec_lat_2, s3); printf("%f %f %f %s\n", deg_long_2, min_long_2, sec_long_2,s4); printf("%c", getchar()); return(0); } void read_GPS(float *degrees,float *minutes,float *seconds,char *direction) { scanf("%f%f%f%s", degrees, minutes, seconds, direction); return; } float convert_DD(float *degrees, float *minutes, float *seconds) { float dec_deg,totalmins; totalmins = *minutes + (*seconds / 60); dec_deg = (totalmins /60) + *degrees; printf("The decimal degree is %f", dec_deg); printf("%c", getchar()); return(dec_deg); } float calc_SphereCoord_lat(char *direction, float *dec_deg) { int temp_1; float phi; char s5[] = "North"; temp_1 = strcasecmp(direction,s5); if (temp_1 == 0) phi = 90 - *dec_deg; else phi = 90 + *dec_deg; printf("The spherical co-ordinate phi is: %f\n", phi); return(phi); } float calc_SphereCoord_long(char *direction, float *dec_deg) { int temp; float theta; char s6[] = "East"; temp = strcasecmp(direction,s6); if (temp == 0) theta = *dec_deg; else theta = (-*dec_deg); printf("The spherical co-ordinate theta is: %f\n", theta); return(theta); } float deg2rad(float *dec_deg) { float radians; radians = (*dec_deg * 2 * PI) / 360; printf("%f as radians is: %f\n", *dec_deg, radians); return(radians); } float calc_3DCoord(float *phi, float *theta) { float temp_1, temp_2, temp_3; temp_1 = (RHO * (sin(*phi)) * (cos(*theta))); temp_2 = (RHO * (sin(*phi)) * (sin(*theta))); temp_3 = (RHO * (cos(*phi))); printf("The cartesian co-ordinates are: %f %f %f\n", temp_1, temp_2, temp_3); return(0); } |
2 Everyone: I think it will be better for me to start my own project
http://www.linuxquestions.org/questi...hreadid=120346 2 john23: I think I can help you with it. But can you explain what exetly should it calculate and what's wrong with output? |
Can i please get help with the above program to calculate the surface distance using the function straight_D and surface_D. The straight distance can be calculated by the formula,
d=sqrt((x2-x1)^2+ (y2-y1)^2+(z2-z1)^2) The surface distance can be calculated by the straight line distance above: surface_distance= 2sin(straight_distance/2) Thanks You to anyone who can help, i want to include this in my program to calculate the surface distance! |
John23 you have already posted your question in a separate thread.
http://www.linuxquestions.org/questi...666#post623666 Please refrain from doing this again in the future. Gary |
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