How use CUT -d 'delimiter' is delimiter is a TAB?
 

How use CUT -d 'delimiter' is delimiter is a TAB?

:(
Any ideas. Google is not helping much :(
Best regards

[ SOLVED ]

MAN CUT is better and cuter than google cut.

take the first string
take the second string


[ SOLVED ]

Just for the next search user.
1) that solution correctly states that TAB is default delimiter for cut.
2) "cut -f1 -s myfile" works on its own, so cat invocation is redundant
3) and are useful to know - just as examples of shell escaping

you can also use awk.

press "<CTR> v" then the "<TAB>" key

cut -d "<CTR>v <TAB>"

Oh thanks that a cool trick too.
By the way if one type :
it doesnt output

That's because word splitting makes the tab just ordinary whitespace to delimit parameters with. If you're really using Bash and not POSIX sh, then use $'\t' and Parameter Expansions. Or even play with IFS and use read:

Depending on the input format, sometimes using "tr -s ' '" will sqeeze extra spaces to a single space letting cut or awk work properly with a space as the delimiter.

example:

ls -l | tr -s ' ' | cut -d' ' -f1,8-

I use the awk
 

grep "833" session_20100321.log | awk '{ FS = "\t" ; printf(" %s %s\n", $5,$6); }'

If your looking to use with ps then:

works :)

use this
 

cut -d$'\t'

When not in bash, use printf:

Thanks man, don't know why AWK slips my mind always!