how to use script sed with full path
 

I have a script like that

find `pwd` | sed -e "s\^.*root\/test/./"

I get an error if I use a parameter replace the path like that

my_path=root/test
find `pwd` | sed -e "s\^.*$my_path/./"

what should I do?

my_path=root\/test
find `pwd` | sed -e 's/^.*'"$my_path"'/./'

It does not work.
error occur


if I take out the single quotation mark like that, no error occur.
find `pwd` | sed -e 's/^.*"$my_path"/./'
however, the sed will not replace the pre-fix "root/test" to "."


What is the different between single quotation mark and double quotation mark in sed?

It's the shell, not sed, that is parsing the quotes. Double quotes allow variable interpolation, single quotes don't. There's a fair bit of info in the bash man page about it (I'm assuming your shell is bash).

You could also use a different separator for the substitute command in sed - then you shouldn't need to quote the variable. I'm not at a box I can test that on at the moment though.

thanks. yes, it is bash shell.
how do define another separator for the command in sed?

Hello gilead if it's ok i'll tell him for you. You can use the @ sign in sed if you like.

Punctuation marks are popular. For an alternative, I go with colon ':', seems to stand out nicely when reading, esp if you are sed'ing dir paths.

Thank you everyone
The problem is solved.